Credit Point Define
| University of Computer Studies (Kalay) | |||
|---|---|---|---|
| No. | Marks | Letter Grade | Grade Point |
| 1 | >90 | A | 4 |
| 2 | 85 - 89 | A- | 3.75 |
| 3 | 80 - 84 | B+ | 3.25 |
| 4 | 75 - 79 | B | 3 |
| 5 | 70 - 74 | B- | 2.75 |
| 6 | 65 - 69 | C+ | 2.25 |
| 7 | 60 - 64 | C | 2 |
| 8 | 55 - 59 | C- | 1.75 |
| 9 | 50 - 54 | D | 1 |
| 10 | <50 | F | 0 |
| Fail Grade and Re-Exam | C-, D, F | Grade Point < 2 |
Example,
Student gets the following marks in semester I
Total mark obtained 100% include Exam+ Tutorial+ lab+ Assignment+ project+ presentation + Attendance
| No. | Subject | Credit Unit | Total Marks Obtained 100% | Grade | Grade Score | Credit Point |
|---|---|---|---|---|---|---|
| 1 | Myanmar | 2 | 70 | B- | 2.75 | 5.5 |
| 2 | English | 3 | 75 | B | 3 | 9 |
| 3 | Physics | 3 | 68 | C+ | 2.25 | 6.75 |
| 4 | Maths | 3 | 86 | A- | 3.75 | 11.25 |
| 5 | Principle of IT | 3 | 92 | A | 4 | 12 |
| 6 | Supporting Skills | 2 | 55 | C- | 1.75 | 3.5 |
| Total Credit Unit | 16 | Total Grade Point | 48 | |||
| Commutative GPA for each Semester | 3.0 | |||||
| Overall GPA | 3.0 | |||||
After Semester I, student’s cumulative GPA is 3.00.
Cumulative GPA = Total Grade point /total credit unit
Overall GPA = ∑ Cumulative GPA for each semester /total semester
Student gets the following marks in semester II
| No. | Subject | Credit Unit | Total Marks Obtained 100% | Grade | Grade Score | Credit Point |
|---|---|---|---|---|---|---|
| 1 | Myanmar | 2 | 68 | C+ | 2.25 | 4.5 |
| 2 | English | 3 | 70 | B- | 2.75 | 8.25 |
| 3 | Physics | 3 | 55 | C- | 1.75 | 5.25 |
| 4 | Maths | 3 | 84 | B+ | 3.25 | 9.75 |
| 5 | Principle of IT | 3 | 89 | A- | 3.75 | 11.25 |
| 6 | Supporting Skills | 2 | 65 | C+ | 2.25 | 4.5 |
| Total Credit Unit | 16 | Total Grade Point | 43.5 | |||
| Commutative GPA for each Semester | 2.72 | |||||
| Overall GPA | 2.86 | |||||
After Semester II, student’s cumulative GPA is 2.72 and Overall GPA is 2.86.
